If x=32 and x=−3 are roots of the quadratic equation ax2+7x+b=0, find the value of a and b.
If x=32,x=−3 are roots of the equation ax2+7x+b=0 then
(x−32)(x−(−3))=0
⇒(x−32)(x+3)=0
⇒x2−32x+3x−2=0
⇒x2+37x−2=0
⇒3x²+7x−6=0
Compare the equation with ax²+7x+b=0
Therefore, a=3,b=−6
Rakhi Thakur Answered question 8 Sep, 2023